If `y=tan^(-1){((log)_e(e//x^2))/((log)_e(e x^2))}+tan^(-1)((3+2\ (log)_e x)/(1-6\ (log)_e x))` , then `(d^2y)/(dx^2)=` (a) 2 (b) 1 (c) 0 (d) -1

Explanation

To solve the problem step by step, we start with the given function:

\[ y = \tan^{-1}\left(\frac{\log_e\left(\frac{e}{x^2}\right)}{\log_e(e x^2)}\right) + \tan^{-1}\left(\frac{3 + 2 \log_e x}{1 - 6 \log_e x}\right) \]

### Step 1: Simplify the first term

The first term can be simplified as follows:

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