Let `f(x)` be a polynomial. Then, the second order derivative of `f(e^x)` is `f"(e^x)e^(2x)+f'(e^x)e^x` (b) `f"(e^x)e^x+f'(e^x)` (c) `f"(e^x)e^(2x)+f"(e^x)e^x` (d) `f"(e^x)`

Explanation

Correct answer is a

Since f(x) is polynomial

` therefore f^'(e^x) = f^'(e^x)e^x`

`rightarrow f^''(e^x)= f^''(e^x)(e^x)^2+f^'(e^x)e^x`

`rightarrow f^''(e^x){e^2x} + f^(e^x)e^x`