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If y^(1/m)+y^(-1/m) = 2x then (x^2-1)y2+...

If `y^(1/m)+y^(-1/m) = 2x` then `(x^2-1)y_2+xy_1` is equal to

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We have `y^{1 / m}+y^{-1 / m}=2 x`
` Rightarrow {y}^{1 / {m}}+frac{1}{{y}^{1 / {m}}}=2 {x} `
` ({y}^{1 / {m}})^{2}-2 {xy}`
` Therefore, y^{1 / m}=x pm sqrt{x^{2}-1}`
` y=[x pm sqrt{x^{2}-1}]^{m}`
...
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