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The volume of a sphere is increasing at ...

The volume of a sphere is increasing at the rate of `4pi` `cm^3//sec` . The rate of increase of the radius when the volume is `288pi` `cm^3` , is

A

(a) `1/6`

B

(b) `1/9`

C

(c) `1/36`

D

(d) `1/24`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these procedures: ### Step 1: Understand the relationship between volume and radius The volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius of the sphere. ### Step 2: Differentiate the volume with respect to time To find the rate of change of the radius with respect to time, we first differentiate the volume with respect to time \( t \): \[ \frac{dV}{dt} = \frac{d}{dt} \left( \frac{4}{3} \pi r^3 \right) \] Using the chain rule, we have: \[ \frac{dV}{dt} = \frac{4}{3} \pi \cdot 3r^2 \frac{dr}{dt} = 4 \pi r^2 \frac{dr}{dt} \] ### Step 3: Substitute the known values We know from the problem that \( \frac{dV}{dt} = 4\pi \, \text{cm}^3/\text{sec} \) and we need to find \( \frac{dr}{dt} \) when the volume \( V = 288\pi \, \text{cm}^3 \). ### Step 4: Find the radius when the volume is \( 288\pi \) To find the radius \( r \) when the volume is \( 288\pi \), we set up the equation: \[ 288\pi = \frac{4}{3} \pi r^3 \] Dividing both sides by \( \pi \): \[ 288 = \frac{4}{3} r^3 \] Multiplying both sides by \( \frac{3}{4} \): \[ r^3 = 288 \cdot \frac{3}{4} = 216 \] Taking the cube root of both sides: \[ r = \sqrt[3]{216} = 6 \, \text{cm} \] ### Step 5: Substitute \( r \) back into the differentiated equation Now we substitute \( r = 6 \, \text{cm} \) into the differentiated equation: \[ 4\pi = 4\pi (6^2) \frac{dr}{dt} \] This simplifies to: \[ 4\pi = 4\pi \cdot 36 \frac{dr}{dt} \] Dividing both sides by \( 4\pi \): \[ 1 = 36 \frac{dr}{dt} \] ### Step 6: Solve for \( \frac{dr}{dt} \) Now, we solve for \( \frac{dr}{dt} \): \[ \frac{dr}{dt} = \frac{1}{36} \, \text{cm/sec} \] ### Final Answer The rate of increase of the radius when the volume is \( 288\pi \, \text{cm}^3 \) is: \[ \frac{dr}{dt} = \frac{1}{36} \, \text{cm/sec} \] ---

To solve the problem step by step, we will follow these procedures: ### Step 1: Understand the relationship between volume and radius The volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius of the sphere. ...
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