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It is given that for the function `f(x)=x^3-6x^2+a x+b` on `[1,\ 3]` , Rolles theorem holds with `c=2+1/(sqrt(3))` . Find the values of `a` and `b` , if `f(1)=f(3)=0` .

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Given` f(1)=f(3)=0`
`1^3−6×1+a+b=3^3−6×3^2+3a+b=0`
`\Rightarrow a+b−5=0 and 3a+b−27=0`
on solving ...
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