Verify Rolles theorem for the function: `f(x)=sinx-sin2x` on `[0,\ pi]`

Explanation

Solution:

`f(x)` is continous differentiable in `[0, \pi]`


`\{f}(0)=\{f}(\pi) \quad \{a}=0 ; \{b}=\pi`


We have to find c in `[0,1]`,

such that, `f^{\prime}(c)=0` (in Rolle's Theorem)

`Rightarrow \cos c-2 \cos 2 c=0 `

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