At what points on the curve `y=e^1-x^2` on `[-1,\ 1]` is the tangent parallel to x-axis?

Explanation

Here is Solution:

Given function is:

`y=e^1-x^2`

As we know that exponential functions are continuous and differentiable over R.

Let’s check the values of y at the extremums


`\Rightarrow {y}(-1)={e}^{1-1} `

`\Rightarrow {y}(-1)={e}^{0} \Rightarrow {y}(-1)=1 `

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