Verify Lagranges mean value theorem for function `f(x)=x(x-1)` on `[1,\ 2]` and find a point `' c '` in the indicated interval:

Explanation

Solution:

`f(x)=x-1`

`f(x)=x^2-x`

`f(x)` is polynomial

`f(x)` is continuous and differentiable at` [1,2]`

`f(x)=2x-1`

`f'(c)=[f(b)-f(a)]/[b-a]`

`f'(c)=[f(2)-f(1)]/[2-1]`

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