Show that the function `f(x)=x^2` is neither strictly increasing nor strictly decreasing on `R` .

Explanation

It is given that `f(x) = x^2 `

By differentiating w.r.t x `f’(x) = 2x > 0`

for x ∈ (0, ∞)

Here f’(x) > 0 which means 2x > 0

So we get x > 0

Thus f(x) is strictly increasing on [0, ∞)

and f(x) is strictly increasing on `(-oo,\ 0]`

Thus, `f(x)=x^2`
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