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Show that for ageq1,\ \ f(x)=sqrt(3)sinx...

Show that for `ageq1,\ \ f(x)=sqrt(3)sinx-cosx-2a x+b` is decreasing on `R` .

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We have a ≥1`,f(x)=√3sinx−cosx−2ax+b`
`f′(x)=√3cosx−(−sinx)−2a`
=`√3cosx+sinx−2a`
=`2[√3/2.cosx+12sinx]−2a`
=`2[cosπ/6.cosx+sinπ/6.sinx]−2a`
=`2(cos(π/6)−x)−2a`
=`2[(cos(π/6)−x)−a]`
We know that, `cosxϵ[−1,1]` ...
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