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Show that f(x)=sinx-cosx is an increasin...

Show that `f(x)=sinx-cosx` is an increasing function on `(-pi//4,\ pi//4)` .

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We have given
`f(x)=sinx-cosx`
Then we have to show, `f(x)` is increasing function on `(-pi/4,pi/4)`
`f(x)=sinx−cosx`
`f′(x)=cosx+sinx`
`f(x)=sqrt2(1/(sqrt2)cosx+1/(sqrt2)sinx)`
`f(x)=sqrt2sin(pi/4+x)`>`0 in pi/4+x in(-pi/2,pi/2)`
`-pi/2`<`pi/4+x`<`pi/2`
...
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