Find the maximum and minimum values of `f(x)=16 x^2-16 x+28` on `R` , if any, without using derivatives.

Explanation

`f(x)=16 x^{2}-16 x+28`
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f(x)=16 x^{2}-16 x+4+24`
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therefore f(x)=(4 x-2)^{2}+24`


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