Find the maximum and minimum values of `f(x)=2x^3-24 x+107` in the interval `[1,\ 3]` .

Explanation

We have,

`f(x)=2x^3-24x+107`

`=> f'(x)=6x^2-24`

For the critical points ,

`f'(x)=0`

`=> 6x^2-24=0`

`=> x^2=4`

`=>x=pm2`

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