Tangent to the circle `x^2+y^2=a^2` at any point on it in the first quadrant makes intercepts `O A` and `O B` on `x` and `y` axes respectively, `O` being the centre of the circle. Find the minimum value of `O A+O B` .

Explanation

To find the minimum value of \( OA + OB \) where \( OA \) and \( OB \) are the intercepts made by the tangent to the circle \( x^2 + y^2 = a^2 \) at a point in the first quadrant, we can follow these steps:

### Step 1: Identify the point on the circle
Let the point \( P \) on the circle in the first quadrant be represented in parametric form as:
\[ P = (a \cos \theta, a \sin \theta) \]
where \( \theta \) is the angle made with the positive x-axis.
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