cot^(-1)x+cot^(-1)2x=(3 pi)/(4)

Solve : cot^(-1)2x+cot^(-1)3x=(pi)/(4)

cot ^(-1)""x+cot^(-1)""2x=(3pi)/(4)

If cot^(-1)x+cot^(-1)y+cot^(-1)z=(pi)/(2) , then x+y+z=

If cot^(-1)x+cot^(-1)y+cot^(-1)z=(pi)/(2) , then x+y+z=

If cot^(-1)x+cot^(-1)y+cot^(-1)z=(pi)/(2) , then x+y+z=

Find x, if tan^(-1)4+cot^(-1)x=(pi)/(2) .

If tan^(-1)4+cot^(-1)x=(pi)/(2), then value of x is

Prove that cot^(-1) 7 + 2 cot^(-1)3 = pi/4

tan^(-1)x +tan^(-1)y = (3pi)/4 Then cot^(-1) x + cot^(-1) y is :

The solution set of inequality (cot^(-1)x)(tan^(-1)x)+(2-(pi)/(2))cot^(-1)x-3tan^(-1)x-3(2-(pi)/(2))>0 is (a,b), then the value of cot ^(-1)a+cot^(-1)b is