The total cost of producing `x` radio sets per day is `R sdot((x^2)/4 35 x+25)` and the price per set at which they may be sold is `R sdot(50-x/2)dot` Find the daily output to maximize the total profit.

Explanation

Profit `P` is given by


` P =`Revenue-Cost=Rs. 1 `{(50-frac{x}{2}) x-(frac{x^{2}}{4}+35 x+25)}= { Rs. } `

`(-frac{3}{4} x^{2}+15 x-25) `

`P=(-frac{3}{4} x^{2}+15 x-25)`

differentiating the above equation, we get,


`frac{d P}{d x}=-frac{3}{2} x+15`
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