A manufacturer can sell x items at a price of Rs. `(5-x/(100))` each. The cost price of `x` items is Rs. `(x/5+\ 500)dot\ ` Find the number of items he should sell to earn maximum profit.

Explanation

Given that manufacturer sells `x` items at a price of Rs `(5-x / 100)` each.

`therefore` Total revenue obtained

`=₹[x(5-frac{x}{100})]=₹(5 x-frac{x^{2}}{100})`


Also, cost price of `x` items `=₹(frac{x}{5}+500)`

Let `P(x)` be the profit function.

We know that,

Profit `=` Revenue `-cos t`
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