`x+sqrt(xy)+y=1`

Solution of the differential equation (y+x sqrt(xy)(x+y))dx+(y sqrt(xy)(x+y)-x)dy=0 is

Convert the following equations into simultaneous equations and solve: sqrt(x/y)=4,1/x+1/y=1/(xy) .

If sqrt(x)+sqrt(y)=17 and sqrt(x)-sqrt(y)=1, then the value of is sqrt(xy)

If x,y in R satisfy the equation x^(2)+y^(2)-4x-2y+5=0, then the value of the expression ((sqrt(x)-sqrt(y))^(2)+4sqrt(xy))/((x+sqrt(xy))) is

If y = (x+ sqrt(x ^(2) -1))^(m) then (x ^(2) -1) y_(2) + xy _(1)=

y=(x^(2))/(2)+(1)/(2)x sqrt(x^(2)+1)+ln sqrt(x+sqrt(x^(2)+1)) prove that 2y=xy'+ln y'

Convert the following equations into simultaneous equations and solve: sqrt((x)/(y))=4,(1)/(x)+(1)/(y)=(1)/(xy)