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The function f(x)=sum(r=1)^5(x-r)^2 ...

The function `f(x)=sum_(r=1)^5(x-r)^2` assuming minimum value at `x=` (a)`5` (b) `5/2` (c)` 3` (d)` 2`

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`f(x)=sum_(r=1)^5(x−r)^2`
To find the extremum points we differentiate and equate it to zero
`\Rightarrow f′(x)=2 sum_(r=1)^5(x−r)`
`\Rightarrow f′(x)=2(5x−15)` ...
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