If `f(x)=1/(4x^2+2x+1)` , then its maximum value is
(a) `4/3`
(b) `2/3`
(c) 1
(d) `3/4`

Explanation

To find the maximum value of the function \( f(x) = \frac{1}{4x^2 + 2x + 1} \), we will follow these steps:

### Step 1: Find the first derivative \( f'(x) \)
To find the critical points, we first need to compute the derivative of \( f(x) \).

Using the quotient rule, we have:
\[
f'(x) = \frac{0 \cdot (4x^2 + 2x + 1) - 1 \cdot (8x + 2)}{(4x^2 + 2x + 1)^2}
...