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The function f(x)=2x^3-15 x^2+36 x+4 is ...

The function `f(x)=2x^3-15 x^2+36 x+4` is maximum at `x=` (a) 3 (b) 0 (c) 4 (d) 2

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`2`
Given : `f(x)=2 x^{3}-15 x^{2}+36 x+4 Rightarrow f^{prime}(x)=6 x^{2}-30 x+36`
For a local maxima or a local minima, we must have
`f^{prime}(x)=0 `
`Rightarrow 6 x^{2}-30 x+36=0`
`Rightarrow x^{2}-5 x+6=0 `
...
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