Let `f(x)=2x^3-3x^2-12 x+5` on `[-2,\ 4]` . The relative maximum occurs at `x=` `-2` (b) `-1` (c) 2 (d) 4

Explanation

To find the relative maximum of the function \( f(x) = 2x^3 - 3x^2 - 12x + 5 \) on the interval \([-2, 4]\), we will follow these steps:

### Step 1: Find the first derivative of the function
We start by differentiating the function to find \( f'(x) \).

\[ f'(x) = \frac{d}{dx}(2x^3 - 3x^2 - 12x + 5) \]
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