Evaluate: `intsqrt(1-sin2x)\ dx`

Explanation

To evaluate the integral \( \int \sqrt{1 - \sin 2x} \, dx \), we will follow these steps:

### Step 1: Rewrite the expression inside the square root
We start with the expression \( 1 - \sin 2x \). We can use the identity for \( \sin 2x \):
\[ \sin 2x = 2 \sin x \cos x \]
Thus, we can rewrite:
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