If `f^(prime)(x)=3x^2-2/(x^3)` and `f(1)=0` , find `f(x)` .

Explanation

`f^{\prime}(x)=3 x^{2}-\frac{2}{x^{3}}` and `f(1)=0`, find `f(x)=`


integrating on both sides,



`f(x) =\int(3 x^{2}-\frac{2}{x^{3}}) d x `


`=\frac{3 x^{3}}{3}-2 \frac{x^{-3}}{-3+1}+c `

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