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Evaluate: (i) intsec^2(7-4x)\ dx (ii) ...

Evaluate:
(i) `intsec^2(7-4x)\ dx`
(ii) `int1/(sin^2xcos^2x)\ dx`

Text Solution

Verified by Experts

(i) `intsec^2(7-4x)\ dx`

Let, `7-4x=t`

`-4dx=dt`

`=(-1)/(4)intsec^2(t)\ dt`

`=(-1)/(4)tan(t)+C`

`=(-1)/(4)tan(7-4x)+C`

(ii) `int1/(sin^2xcos^2x)\ dx`

`=int(sin^2x+cos^2x)/(sin^2xcos^2x))\dx`

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