`int(2x-3)^5+sqrt(3x+2)\ dx`

Explanation

To solve the integral \( \int (2x - 3)^5 + \sqrt{3x + 2} \, dx \), we can break it down into two separate integrals:

1. \( \int (2x - 3)^5 \, dx \)
2. \( \int \sqrt{3x + 2} \, dx \)

### Step 1: Solve \( \int (2x - 3)^5 \, dx \)

To integrate \( (2x - 3)^5 \), we can use the substitution method. Let:
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