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int1/(2-3x)+1/(sqrt(3x-2))\ dx...

`int1/(2-3x)+1/(sqrt(3x-2))\ dx`

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`=int1/(2-3x)+1/(sqrt(3x-2))\ dx`

Let, `2-3x=t` and `3x-2=z`

`dx=(dt)/(-3)` and `dx=dz/3`

`=(-1)/(3)int1/(t)dt+int1/(3sqrt(z))dz`

`=(-1)/(3)ln(t)+(2sqrt(z))/(3)+C`

`=(-1)/(3)ln(2-3x)+(2sqrt(3x-2))/(3)+C`

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