`int1/(sqrt(2x+3)+sqrt(2x-3))\ dx`

Explanation

To solve the integral \( \int \frac{1}{\sqrt{2x+3} + \sqrt{2x-3}} \, dx \), we will follow these steps:

### Step 1: Rationalize the Denominator
We start by multiplying the numerator and denominator by the conjugate of the denominator:

\[ \int \frac{1}{\sqrt{2x+3} + \sqrt{2x-3}} \, dx \cdot \frac{\sqrt{2x+3} - \sqrt{2x-3}}{\sqrt{2x+3} - \sqrt{2x-3}} = \int \frac{\sqrt{2x+3} - \sqrt{2x-3}}{(\sqrt{2x+3})^2 - (\sqrt{2x-3})^2} \, dx \]
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