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Evaluate: (i) int(secx)/(sec2x)\ dx (ii)...

Evaluate: (i) `int(secx)/(sec2x)\ dx` (ii) `int(cos2x)/((cosx+sinx)^2)\ dx`

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(i) First of all convert `sec x` in terms of `cos x`
As we know
`sec x=1 / cos x, sec 2 x=1 / cos 2 x`
So, the above equation becomes,
`Rightarrow frac{frac{1}{cos x}}{frac{1}{cos 2 x}} `
...
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