underset(-pi//2)overset(pi//2)int sin^3 ...

`underset(-pi//2)overset(pi//2)int sin^3 xdx`

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The correct Answer is:

underset(-3)overset(3)int |x+1|dx
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underset(0)overset(pi/2)int sin^(2)x cos^(3)x dx
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underset(-pi//2)overset(pi//2)int sin^3 xdx
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underset(-pi//2)overset(pi//2)int sin^2x dx
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underset(2)overset(8)int |x-5|dx
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underset(0)overset(1)int x(1-x)^(n)dx
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underset(-2)overset(2)int |2x+3|dx
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underset(0)overset(2)int |x^(2)-3x+2|dx
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underset(0)overset(pi//2)int (dx)/(1+tanx)
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underset(0)overset(pi//2)int (sin^(3//2)x)/(sin^(3//2)x+cos^(3//2)x)dx
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underset(0)overset(pi//2)int (sqrtcotx)/(sqrt(cot x)+sqrt(tan x))
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underset(0)overset(pi//2)int (1)/(1+cot x)dx
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underset(0)overset(pi//2)int (sin x)/(sin x+cos x)dx
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underset(0)overset(pi)int (x tan x)/(sec x+tan x)dx
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underset(0)overset(a)int (1)/(x+sqrt(a^(2)-x^(2)))dx
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underset(0)overset(pi//2)int (sin^(n)theta)/(sin^(n)theta+cos^(n)theta...
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underset(0)overset(oo)int (x)/((1+x)(1+x^(2)))dx
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underset(0)overset(pi//2)int (2log cos x-log sin 2x)dx
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underset(0)overset(pi)int x sin x cos^(4)xdx
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underset(0)overset(pi)int (x tanx)/(sec x "cosec x")
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