underset(0)overset(pi//2)int |sin x-cos ...

`underset(0)overset(pi//2)int |sin x-cos x|dx`

Verified by Experts

The correct Answer is:

`2(sqrt2-1)`

underset(1)overset(3)int |x^(2)-2x|dx
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underset(0)overset(1)int |2x-1|dx
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underset(0)overset(pi//2)int |sin x-cos x|dx
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underset(-a)overset(a)int (x e^(x^(2)))/(1+x^(2))dx
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underset(-pi//2)overset(pi//2)int sin^(9)xdx
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underset(0)overset(1.5)int |x^(2)|dx
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underset(-pi)overset(pi)int x^(10)sin^7 xdx
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underset(0)overset(1)int cos^(-1)((1-x^(2))/(1+x^(2)))dx
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underset(1)overset(5)int (x)/(sqrt(2x-1))dx
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underset(1)overset(2)int xsqrt(3x-2)dx
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underset(0)overset(4)int xsqrt(4-x)dx
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underset(0)overset(1)int cos^(-1)xdx
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underset(0)overset(pi)int sin^(3)x(1+2cos x)(1+cos x)^(2)dx
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underset(0)overset(pi//3)int (cos x)/(3+4sinx)dx
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underset(0)overset(pi//2)int (sin^(2)x)/((1+cosx)^(2))dx
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underset(0)overset(1)int sqrt((1-x)/(1+x))dx
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underset(1)overset(2)int (1)/(x^(2))e^(-1//x)dx
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underset(0)overset(pi//4)int e^(x) sin xdx
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underset(1)overset(2)int (x+3)/(x(x+2)) dx
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underset(0)overset(1)int log(1+x)dx
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