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int(x^2)/(sqrt(3x+4))\ dx (ii) int(2x-1)...

`int(x^2)/(sqrt(3x+4))\ dx` (ii) `int(2x-1)/((x-1)^2)\ dx`

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Let's solve the two integrals step by step. ### Integral 1: \(\int \frac{x^2}{\sqrt{3x + 4}} \, dx\) **Step 1: Substitution** Let \( t = 3x + 4 \). Then, differentiate to find \( dx \): \[ dt = 3 \, dx \quad \Rightarrow \quad dx = \frac{dt}{3} ...
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