Evaluate: `int1/(sqrt(4x^2-9))\ dx`

Explanation

To evaluate the integral \( \int \frac{1}{\sqrt{4x^2 - 9}} \, dx \), we can follow these steps:

### Step 1: Rewrite the integrand
We can rewrite the expression under the square root:
\[ \sqrt{4x^2 - 9} = \sqrt{(2x)^2 - 3^2} \]
This suggests that we can use a trigonometric substitution or a standard integral formula.
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