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Evaluate: int1/(2x^2-x-1)dx...

Evaluate: `int1/(2x^2-x-1)dx`

Text Solution

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`2 x^{2}-x-1=1 / 2(x^{2}-x / 2-1 / 2) `
`=1 / 2(x^{2}-x / 2+1 / 16-1 / 16-1 / 2) `
`=frac{1}{2}[(x-frac{1}{4})^{2}-frac{1}{16}-frac{1}{2}] `
`=frac{1}{2}[(x-frac{1}{4})^{2}-frac{9}{16}] `
`=frac{1}{2}[(x-frac{1}{4})^{2}-(frac{3}{4})^{2}]`
So integral becomes,
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