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Evaluate: int(sec^2x)/(1-tan^2x)\ dx...

Evaluate: `int(sec^2x)/(1-tan^2x)\ dx`

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To evaluate the integral \( \int \frac{\sec^2 x}{1 - \tan^2 x} \, dx \), we can follow these steps: ### Step 1: Rewrite the integral We know that \( \sec^2 x = 1 + \tan^2 x \). Therefore, we can rewrite the integral as: \[ \int \frac{\sec^2 x}{1 - \tan^2 x} \, dx = \int \frac{1 + \tan^2 x}{1 - \tan^2 x} \, dx \] ...
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