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Evaluate: int1/((x-alpha)(beta-x))dx ,(b...

Evaluate: `int1/((x-alpha)(beta-x))dx ,(beta>alpha)`

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I=`int1/((x-alpha)(beta-x))dx ,(beta>alpha)`
Let,
`x=alphacos^2theta+betacos^2theta`
`x−alpha=alphasin^2theta+betacos^2theta−alpha=(beta−alpha)cos^2theta`
And,
`beta−x=beta−alphasin^2theta−betacos^2theta =(beta−alpha)sin^2theta`
And,
...
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