Evaluate: `int1/(x\ sqrt(4-9\ (logx)^2))\ dx`

Explanation

I=`int1/(x\ sqrt(4-9\ (logx)^2))\ dx`

let `3logx=t`

`3/xdx=dt`

So,

`I=1/3int(dt)/(sqrt(2^2-t^2)) dx`

`I=1/3 sin^(-1)(t/2)+c`

`I=1/3 sin^(-1)((3logx)/2)+c`