Evaluate: `int(sin2x)/(sqrt(sin^4x+4sin^2x-2))\ dx`

Explanation

Let `t = sin^2x`

`dt = 2sinx cosx dx`

Given,

I=`int(sin2x)/(sqrt(sin^4x+4sin^2x-2))\ dx`

I=`int(dt)/(sqrt(t^2+4t-2))\ dx`

I=`int(dt)/(sqrt(t^2+4t-2+4-4))\ dx`

I=`int(dt)/(sqrt((t+2)^2-6))\ dx`

let `t+2=u`

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