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Evaluate: int(cosx)/(sqrt(sin^2x-2sinx-3...

Evaluate: `int(cosx)/(sqrt(sin^2x-2sinx-3))\ dx`

Text Solution

Verified by Experts

I= `int(cosx)/(sqrt(sin^2x-2sinx-3))\ dx`
I= `int(cosx)/(sqrt((sinx-1)^2sinx-2^2))\ dx`
Let `sinx−1=t`
`⇒cosx.dx=dt`
Substituting we get-
`I=int (dt)/(sqrt(t^2-2^2))`
`=log∣t+sqrt(t^2−2^2)​∣​+C`
`=log∣​(sinx−1)+sqrt((sinx−1)^2−4 ...
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Knowledge Check

  • int(cosx)/(sqrt(sin^2x-sinx-3))dx=

    A
    `log|sinx+1+sqrt(sin^2-2sinx-3)|+c`
    B
    `log|sinx+1-sqrt(sin^2-2sinx-3)|+c`
    C
    `log|sinx-1+sqrt(sin^2-2sinx-3)|+c`
    D
    `log|sinx-1-sqrt(sin^2-2sinx-3)|+c`
  • int(cosx)/(sqrt(sin^2x-2sinx+5))dx=

    A
    `log|sinx-1+sqrt(sin^2x-2sinx+5)|+c`
    B
    `-log|sinx-1+sqrt(sin^2x-2sinx+5)|+c`
    C
    `log|sinx+1+sqrt(sin^2x+2sinx+5)|+c`
    D
    `-log|sinx+1+sqrt(sin^2x+2sinx+5)|+c`
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