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Evaluate: int(2x-3)/(x^2+3x-18)\ dx...

Evaluate: `int(2x-3)/(x^2+3x-18)\ dx`

Text Solution

Verified by Experts

I=`int(2x-3)/(x^2+3x-18)\ dx`
I=`int(2x+3-6)/(x^2+3x-18)\ dx`
I=`int(2x+3)/(x^2+3x-18)\ dx`-`int(6)/(x^2+3x-18)\ dx`
let `x^2+3x-18=t`
`(2x+3)dx=dt`
So,
`I=int(dt)/t-int(6)/((x+3/2)^2-(9/2)^2)\ dx`
`I=log(x^2+3x-18)-6**(1/(9/2))log((x+3/2-9/2)/(x+3/2+9/2))+c`
...
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