Evaluate: `int(x+1)/(sqrt(x^2+1))\ dx`

Explanation

I= `int(x+1)/(sqrt(x^2+1))\ dx`

I=`int(x)/(sqrt(x^2+1))\ dx`+`int(1)/(sqrt(x^2+1))\ dx`


`I=I_1+i_2`

`I_1=``int(x)/(sqrt(x^2+1))\ dx`

let `x^2+1=t`

`2xdx=dt`

so,

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