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Evaluate: int1/(1-cotx)\ dx...

Evaluate: `int1/(1-cotx)\ dx`

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We have given
`int 1/(1-cotx) dx`
`I=int 1/(1-cotx) dx`
`I=int (sinx)/(sinx-cosx)dx`
`I=(1/2)int (2sinx)/(sinx -cosx)dx`
`I=(1/2)int (sinx-cosx)/(sinx-cosx)dx -(1/2)int (cosx-sinx)/(sinx-cosx)dx`
`I=(1/2)intdx+(1/2)int(d(-cosx+sinx))/(sinx-cosx)`
...
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