Evaluate: `intxsin^2x\ dx`

Explanation

We have given `intxsin^2x\ dx`

`I= intxsin^2x\ dx`

`I=xintsin^2xdx-int(intsin^2xdx)dx`

`I=xint (1-cos2x)/2dx-int(int (1-cos2x)/2dx)dx`

`I=x1/2int(1-co2x)dx-int(1/2int(1-co2x)dx)dx`

`I=x/2[x-(sin2x)/2]-int(1/2[x-(sin2x)/2])dx`

`I=(x^2)/4-(xsin2x)/4-1/8cos2x+c`