Evaluate: `intx^2sinx\ dx`

Explanation

We have given `intx^2sinx\ dx`

`I=intx^2sinx\ dx`

By Integrating by parts,

`I=x^2intsinxdx-int[d/(dx)(x^2)intsinxdx]dx`

`I=x^2(-cosx)-2intx(-cosx)dx`

`I=-x^2cosx+2intxcosxdx`

Now again applying integration by parts

`I=-x^2cosx+2[x intcosxdx-intd/(dx)x intcosxdx]`

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