Evaluate: `intsec^(-1)x\ dx`

Explanation

We have given `intsec^(-1)x\ dx`

`I=intsec^(-1)x\ dx`

By integration by parts

`I=int 1.sec^(-1)x\ dx`

`I=xsec^(-1)x-int x.d/(dx)(sec^(-1)x)dx`

Let `sec^(-1)x=t`

`implies x=sect`

`implies dx=secttantdt`

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