Evaluate: `intsinsqrt(x)\ dx`

Explanation

Given integral,
`intsinsqrt(x)\ dx`
taking `sqrtx=t`
`=>x=t^2`
`=>dx=2tdt`
by putting these values given integral becomes,
`intsint *2tdt`
`=2 int tsint dt`
now by integrating the function by parts we get,
`=2[t(-cost)+int1*cost dt]+c`
`=2[sint-t cost]+c`
put the value of `t`
`=2[sinsqrtx-sqrtx cos sqrtx ]+c`