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Evaluate: int{1/(logx)-1/((logx)^2)}\ dx...

Evaluate: `int{1/(logx)-1/((logx)^2)}\ dx`

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To evaluate the integral \[ I = \int \left( \frac{1}{\log x} - \frac{1}{(\log x)^2} \right) dx, \] we can separate it into two integrals: ...
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