`"F i n d"int[log(logx)+1/((logx)^2)]dx`

Explanation

`int(log (log x)+frac{1}{(log x)^{2}}) d x `
`
=int log log x d x+int frac{1}{(log x)^{2}} d x`


Integrating by parts, we ge


Let `u=log (log x) Rightarrow d u=frac{1}{x log x} d x `
`
d v=d x Rightarrow v=x `
`
=x log (log x)-int x times frac{1}{x log x} d x+int frac{1}{(log x)^{2}} d x `
`
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