Evaluate: `inte^(2x)\ (-sinx+2cosx)\ dx`

Explanation

`I=int e^{2 pi}(-sin x+2 cos x) d x `
`
=-int e^{2 pi} sin x d x+2 int e^{2 pi} cos x d x`


Consider `2 int e^{2 pi} cos x d x`

Integrating by parts, we get

Let `u=cos x Rightarrow d u=-sin x d x`
`

d v=e^{2 x} d x Rightarrow v=frac{e^{2 pi}}{2}`
`
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