Evaluate: `intsqrt(3-2x-2x^2)\ dx`

Explanation

To evaluate the integral \( \int \sqrt{3 - 2x - 2x^2} \, dx \), we will follow these steps:

### Step 1: Rewrite the expression under the square root
First, we rearrange the expression inside the square root:
\[ 3 - 2x - 2x^2 = -2x^2 - 2x + 3 \]
Next, we factor out \(-2\):
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